急!!!!!!分解因式3a^3+7a^2-4

来源:百度知道 编辑:UC知道 时间:2024/06/13 00:08:28
简便方法

3a^3+7a^2-4
=3a^3+3a^2+4a^2-4
=3a^2(a+1)+4(a+1)(a-1)
=(a+1)(3a^2+4a-4)
=(a+1)(3a-2)(a+2)

3a^3+7a^2-4
=(3a^3+3a^2)+(4a^2-4)
=3a^2(a+1)+4(a^2-1)
=3a^2(a+1)+4(a+1)(a-1)
=(a+1)[3a^2+4(a-1)]
=(a+1)(3a^2+4a-4)
=(a+1)(a+2)(3a-2)

3a^3+7a^2-4
=3a^3+3a^2+4a^2-4
=3a^2(a+1)+4(a+1)(a-1)
=(a+1)(3a^2-4a-4)
=(a+1)(3a+2)(a-2)

3a^3+7a^2-4=3a^3+3a^2+4a^2-4
=3a^2(a+1)+4(a+1)(a-1)
=(a+1)(3a^2+4a-4)
=(a+1)(a+2)(3a-2).

过程大概是这样的
3a^3+7a^2-4
=3a^3+3a^2+4a^2-4
=3a^2(a+1)+4(a+1)(a-1)
=(a+1)(3a^2+4a-4)
=(a+1)(3a-2)(a+2)
祝你学习进步

3a^3+7a^2-4
=3a^3+3a^2+4a^2+4-8
=3a(a^2+1)+4(a^2+1)-8
=(3a+4)(a^2+1)-8